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0.15X^2-6X+46=0
a = 0.15; b = -6; c = +46;
Δ = b2-4ac
Δ = -62-4·0.15·46
Δ = 8.4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-\sqrt{8.4}}{2*0.15}=\frac{6-\sqrt{8.4}}{0.3} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+\sqrt{8.4}}{2*0.15}=\frac{6+\sqrt{8.4}}{0.3} $
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